(2^2-12x-12x^2)=0

Solution for (2^2-12x-12x^2)=0 equation:

(2^2-12x-12x^2)=0

We get rid of parentheses

-12x^2-12x+2^2=0

We add all the numbers together, and all the variables

-12x^2-12x+4=0

a = -12; b = -12; c = +4;
Δ = b2-4ac
Δ = -122-4·(-12)·4
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{21}}{2*-12}=\frac{12-4\sqrt{21}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{21}}{2*-12}=\frac{12+4\sqrt{21}}{-24}
$